$referer = isset($_SERVER['HTTP_REFERER']) ? $_SERVER['HTTP_REFERER'] : NULL;
$host = $_SERVER['HTTP_HOST'];
echo '提交过来的地址:'.$referer;
echo '<br>';
echo '本站域名:'.$host;
echo '<br>';
echo substr($referer,7,strlen($host));
if(substr($referer,7,strlen($host)) != $host){
echo '非法操作';
}else{
echo '正常操作';
}php防止外部提交表单,禁止跨站提交代码
阅读:4858 输入:2015-12-15 09:10:45